10. Write a program in C to check if a year is a leap year using 'if-else' statements.

The purpose of checking for leap years in programming is to accurately calculate time-related events, such as determining the number of days in a year or adjusting calendars. Leap years are essential for maintaining accurate timekeeping systems.
Real-life applications of checking leap years include calendar systems, scheduling events, financial calculations, and any other situation where precise time calculations are necessary.
Write a program in C to check if a year is a leap year using 'if-else' statements.

/* a program in C to check if a year is a leap year using
if else statements.*/
#include <stdio.h>
int main()
{
int year;
printf("Enter a year: ");
scanf("%d", &year);
if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
{
printf("%d is a leap year.\n", year);
}
else
{
printf("%d is not a leap year.\n", year);
}
return 0;
}

Output:
Enter a Year:
2000
2000 is leap year.

a program in C language to determine if a year is a leap year using 'if-else' statements.

Explanation
Explanation:
1. We first prompt the user to enter a year and store it in the variable 'year'.
2. We then use the 'if-else' statement to check if the year is a leap year.
3. A leap year is divisible by 4 but not by 100, or it is divisible by 400.
4. If the condition is true, we print that the year is a leap year. Otherwise, we print that it is not a leap year.
To explain leap years in detail, you can discuss the concept of leap years, the rules for determining leap years (divisible by 4 but not by 100 unless divisible by 400), historical background, and the significance of leap years in calendars.

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