a C Program that will request the user for a number and then check whether the number is a perfect number.

Problem Solution
1.Take a number as input and store it in a variable.
2.Go through all the numbers from 1 to the number and check if the number is a divisor of the number.
3.If a number divides the number, add it to the sum.
4.If the sum is a number, print "This number is a perfect number".
5.If the number is not equal to sum then show message “The number is not a perfect number”.

C program source code to check whether a given number is perfect number or not using while loop.

#include<stdio.h>
int main(void)
{
 int n, i, sum = 0;
  printf("Enter the number: \n");
 scanf("%d",&n);
 i=1;
 while (i< n)
 {    if(n%i==0)
     sum+=i;
   i++;
 }
 if (sum==n)
   printf("\n%d is a perfect number",n);
 else
   printf("%d is not a perfect number",n);
}
Output
Enter the number: 11
11 is not a perfect number
Enter the number: 28
28 is a perfect number

Explanation
1. Take a number as input and save it as a variable n.
2. Iterate or loop all the numbers from 1 to the number n and check whether the number is divisible by the number or not.
3. Inside the while loop, divide the number by i and save the result in a variable sum.
4. If the sum is equal to a number, print "number is a perfect number".
5. otherwise show message "The number is not a perfect number".

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