14. Write a program in c language to check if a given number is a palindrome or not using a while loop.

Palindrome Number
A number is a palindrome if it reads the same way forward and backward, that is, when the digits of the number are reversed, we get the same number.
For Example: 121, 343.

Problem Description 1.Enter Any number to find the reverse.
2.Reverse the given number.
3.Check whether the reversed number matches the original number.
4.If they are equal, print the number that is palindrome and otherwise print the number that is not palindrome.

Palindrome Program in C using While Loop

/*
* C language Program to Check whether a Number is Palindrome
or Not using While Loop
*/
#include<stdio.h>


int main()
{
    int n,rev=0,num;
    printf("Enter the number:\n");
    scanf("%d", &n);
 
    num=n;  //Store the given number in the variable num
 
    //Reverse the number  n and store it in rev variable
    while(n>0)
    {
        rev=rev*10+n%10;
        n=n/10;
    }
 
    /* check whether original number num is same as reversed number  rev or not*/
    if(num==rev)
        printf("\n%d is a palindrome number.",num);
    else
        printf("\n%d is not a palindrome number.", num);
 
    return 0;
}

a program in c language to check if a given number is a palindrome or not using a while loop.

Output
Enter the number
121
121 is palindrome number.

Explanation
1. Accept any number n as input from the user.
2. Initialize the variable num and put the value n in it, and also initialize rev=0.
3. Run the while loop until n becomes greater than 0.
4. Inside the while loop, reverse the number n using the formula rev=rev*10 + n%10 and recalculate the value of n as n/10 in each iteration.
5. After reversing the number, store it in the rev variable and check whether num is equal to rev or not.
6. If num is equal to rev, show the number as a palindrome.
7. Otherwise, show the number is not palindrome.

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