Sum of digits
Example 1
Given number = 123214 = 1+2+3+2+1+4 =13.
The sum of the digits of the given number "123214" is 13.
Example 2
Given number = 1273 = 1+2+7+3=13.
The sum of the digits of the given number "1273" is 13.
In this method we will divide the number by 10 and add the remainder to the sum.
/*
* C program finds the sum of digits of a any given number number
*/
#include<stdio.h>
int main(void) { int n,sum=0,rem,n1; printf("\nEnter a number:\n"); scanf("%d",&n); n1=n; // Continue dividing until the number becomes zero while(n!=0) { rem=n%10; sum=sum+rem; n=n/10; } printf("\n Sum of digits of the number %d is %d",n1,sum); return 0; }
Output
Enter a number
421
Sum of digits of the number 421 is 7
Explanation
1.Take an integer as input and store it in the variable n.
2.Set the value of the variable to zero.
3.Divide the entered integer by 10 and get the remainder and the quotient.
4.Store the remainder in the rem variable.
5.Increase the sum of the variable with the variable rem.
6.Store the quotient in the variable n.
7.This process is repeated until the number becomes 0.
8.Print the changed amount as output and exit.
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